June 15, 2012 at 12:10 pm
I’m trying to identify the aerial below and wondered if anyone recognised what equipment and/or aircraft it is associated with. From its size, I think it operated on a frequency of around 350 MHz, which is quite close to Instrument Landing System frequencies, but I’m not sure if this is an ILS aerial or something else. Any ILS aerials I’ve seen tend to be horse-shoe shaped, but it could be something along those lines.
If anyone can help identify what set this is the aerial for it would be tremendously helpful.
By: daveg4otu - 16th June 2012 at 08:32
Quarter wave at 158mhz =..
300/158 /4 x.95 =0.45m which is the length of your antenna radiators…so it must be for Marine band..
http://www.garfnet.org.uk/joomla/index.php?option=com_content&view=article&id=95:vhf-marine-band-channels&catid=3:radio-frequencies&Itemid=59
By: RadarArchive - 16th June 2012 at 06:28
Dave,
Thanks for that, which makes sense. I calculate the length of the quarter wave to be approximately 43cm which if my maths is correct would give a frequency of 174.3 MHz. If that’s right, does that give any more indication of the function of the aerial?
By: daveg4otu - 15th June 2012 at 22:09
Normal half wave dipole is 2 quarter waves fed at the center (Highest current/I and lowest voltage/V ) gives good impedance(Z) for matching to TX output .
Usually in the rough calculation you go for about 95% of the calculated length to allow for “end effect” ie: the thickness of the radiator.
By: RadarArchive - 15th June 2012 at 21:21
Dave,
My bad! Thanks for that. I’d always understood each dipole was a half, not a quarter wavelength, but there you go. I’ve definitely learned something new!
If this aerial is marine band VHF for aerial use, is it perhaps off a Shackleton?
By: daveg4otu - 15th June 2012 at 19:50
I make the resonant frequency , calculated from your measurement of 45cm per quarter wave section(2 quarterwaves make a half wavw dipole) to be 158mhz approx.
The calculation …
45cm(one quarter wave) divided by 95 then times 100 (This removes the end effect allowance which will have been calculated in when designing the antenna)=47.37cms.
47.37 x 4=189.48 cm(1.8948m)
300 divided by 1.8948 =158.32 Mhz approx….
At a guess I’d say it’s a marine VHF band antenna….for airborne use.
By: RadarArchive - 15th June 2012 at 17:03
Thanks for the posts. Ignoring the curved bit joining the two dipoles together, each dipole measures 45cm long. From that I figured a wavelength of 90cm which I calculate to a frequency of about 350 MHz (well, actually 333 MHz).
And, no I’m afraid it’s not a V-beam aerial! 🙂
By: Resmoroh - 15th June 2012 at 15:20
Just for a moment, Ian, when I read your thread header I thought you might have been talking about REAL V-beam aerials! You know, a real, tactical, steerable, HF aerial. Hundreds of feet of R4 copper aerial wire all strung from the top of a tactical, air-transportable, 80 foot mast! And the Grainger log-periodic ditto. On one Det it had taken us 2 days (at Stornoway in the winter!) to get this beast up. We finally got in comm with some Fishead boat in the Caribbean with a howling gale blowing and horizontal rain. Suddenly, there was a loud bang and everything went dark and quiet. Investigation showed that one of the local sheep (soaking wet) had decided to ‘scratch an itch’ on the bottom of a live aerial leg. Bang! Dead mutton (still steaming!). Even knocked the Meadows genny off-line!
That, Ian, Old Friend, is a real V-beam aerial. Not your Toytown stuff!
HTH
Resmoroh
By: AlanR - 15th June 2012 at 12:46
What are it’s dimensions ?
At first glance I thought it was off the front of an MC-130E 🙂
That was much more heavy duty though
By: daveg4otu - 15th June 2012 at 12:32
If you have any amateur radio friends with an antenna frequency analyser, a good start would be to stick a bit of 50 ohm coax and a PL259 plug the antenna and find out just what freq it is resonant on.