Maths! HELP!

OK… differentiating gives

1. dy/dx = -3x^2

2. dy/dx = 2x

There’s your gradient… all you need to know now is at what value of x you need the gradient!

What, now? After all this?

Flood.

No really, where do you get them all?

I will be going to my bank manager when i ge the grades i need. I hope to get a loan and apply for OAT.

How bad will I look after telling you guys this!!! I got a D at my Physics GCSE, all you need to be able to do is pass the physics exam for the OAT selection. I had 60 hours physics tuition over the summer and it helped me no end, I ended up getting 87% on the physics paper.

OAT’s looking for good personalities ‘stable extraverts’ as they continually tell us. They are looking more to see what kind of captain you’ll make than if you are a genius. The actual maths and physics on the course are hard, but I get through it, and if I can, I’m sure plenty of others can.

Originally posted by wysiwyg
I failed my first attempt at O level Physics. Mind you, exams were much much harder in those days 😉 !!!! I’ll get my crash hat and prepare for the incoming!

But you hold a physics pass now?

Thats the only real thing stopping me applying to OAT… oh yeah, that and the lack of £30K

I failed my first attempt at O level Physics. Mind you, exams were much much harder in those days 😉 !!!! I’ll get my crash hat and prepare for the incoming!

Originally posted by martin_EGTK
!“Maths, Help!” – My exact thoughts as I sat in a Mass and Balance lecture yesterday! But seriously, I wouldn’t worry too much about your standard, it doesn’t need to be too advanced as the maths is pretty basic and you do the same things so often that even if you don’t get it first time, you’ll work it out sooner or later.

I’m awful at Maths, I got a C at GCSE, but I’m not struggling with the Maths in groundschool, so if I can do it, I’m sure you can

Well thats reassuring. I got the same grade. Interesting.
Only thing I realy lack is Physics.

!“Maths, Help!” – My exact thoughts as I sat in a Mass and Balance lecture yesterday! But seriously, I wouldn’t worry too much about your standard, it doesn’t need to be too advanced as the maths is pretty basic and you do the same things so often that even if you don’t get it first time, you’ll work it out sooner or later.

I’m awful at Maths, I got a C at GCSE, but I’m not struggling with the Maths in groundschool, so if I can do it, I’m sure you can

I am releasing them in to the wild…

Flood.

lol, where u get all these smilies from?

Searching for the lost chord…

Flood.

because my chords prove it

Great.

Doesn’t mean a thing to me – so how do you know its done?

Flood.

At A Y=-X³ At B Y+d = -(X+c)³
y=-x^3
Y+d= -(X+c)³
Y+d= -X³-c³-3X²c-3Xc²
d= X³-c³-3X²c-3Xc²-Y (Y=-X³)
d= -c³-3X²c-3Xc²
d= -c³-3X²c-3Xc²
d= -c(c²+3X²+3Xc)

Gradient AB= d è -c(c²+3X²+3Xc)
c c
Gradient AB= -c²-3X²-3Xc
Gradient at a point when c=0 è 0-3X²-0= -3X²

y=x^2+2
At A Y=X² +2 At B Y+d = (X+c)²+2
Y+d= (X+c)²+2
Y+d= X²+c²+2Xc+2
d= X²+c²+2Xc+2-Y (Y=X²+2)
d= X²+c²+2Xc+2-X² -2
d= c²+2Xc
d= c(c+2X)

Gradient AB= d è c(c+2X)
c c
Gradient AB= c+2X
Gradient at a point when c=0 è 0+2X = 2X

I DID IT!!!!!!! WOO HOO

Flood.

It can be done but i dont know how, here is an example of y=x^2:

Here are my workings out for the gradient of the line y=x²:
At A Y=X² At B Y+d = (X+c)²
Y+d= (X+c)²
Y+d= X²+c²+2Xc
d= X²+c²+2Xc-Y (Y=X²)
d= X²+c²+2Xc-X²
d= c²+2Xc
d= c(c+2X)

Gradient AB= d è c(c+2X)
c c
Gradient AB= c+2X
Gradient at a point when c=0 è 0+2X = 2X

I dont think you can actually do that.The formula you use to find the gradient of somthing is y2-y1overx2-x1

You use y+c y+d to work it out i think, but i dont know how 🙁

You should end up with somthing like 3x which means if you choos 5 as a value for x the gradient at that point is 15.

It’s been 20odd years since I did that kind of maths but I can picture the shape of the curves. I can’t quite see how you can assess the gradient of the curve without stating at which point on the line you wish to measure (assuming you mean the gradient from that point through the origin).