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Rolls-Royce Merlin Reduction-Gear Question?

Simple question; why so big?

Bear with me on this. The reduction-gear on a Rolls-Royce Merlin engine is big; it has a large diameter (about 400mm), is quite thick (about 80mm) and so is also quite heavy. The reduction-gear-pinion is correspondingly big and heavy. So what?

Well, the whole power of the engine is transmitted to the propeller by a much lighter splined shaft that fits into splines within the reduction-gear-pinion and into a splined collar bolted to a flange on the end of the crankshaft. So, if the whole power of the engine is transmitted through these much smaller splines, why such a big reduction-gear?

Possibly the answer is a simple as friction, heat dissipation and wear on the reduction gears as all similar vintage V-12 engines seem to employ these large scale reduction-gears. Anybody know?

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By: Reckless Rat - 2nd March 2014 at 11:03

Do I remember rightly that the skew-gear issue was found to be due to order-of-assembly?

As for gear tooth wear, this also brings up the old chestnut of cycloidal vs. involute teeth forms. In theory, the cycloidal form is subject to less sliding friction as the gear rotates, resulting in less wear. People will try to claim that this is the reason my 200-year-old Grandfather clock is still happily keeping time on the far side of the room. In reality, especially with modern manufacturing methods, it makes little difference. Wikipedia has a good illustration of pressure angles and contact points on involute gears

http://en.wikipedia.org/wiki/Involute_gear

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By: Arabella-Cox - 1st March 2014 at 20:48

It mustn’t half have flexed that bearing panel to cause the skew gears to practically unmesh. It illustrates the forces at work within the engine, sometimes in directions quite unexpected by the designers.

Another description I’d heard of the skew gear failure on the Merlin was “things went bloody quiet up front”.

Anon.

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By: MerlinPete - 1st March 2014 at 20:28

What was the skew gear problem i remember on Merlins ?

The skew gear is on a cross shaft in the wheelcase which, critically, drives both magnetos.
The problem occurred due to the splined quill shaft mentioned above in this thread, which drives the reduction gear pinion.

Bear with me…if the front of the pinion was higher or lower (I forget which) than the back, due to manufacturing tolerances ( the roller bearings at the front and back of the pinion were in different casings), then the crankshaft could be forced backwards with enough force to bend the centre main bearing panel in the crankcase, carrying the thrust bearing, so that the ensuing increased clearance in the bevel gears driving the lower vertical shaft in the wheelcase caused backlash and chatter sufficient to strip the skew gear, which was bronze, causing, to quote Alex Henshaw, “The Deafening Silence”.

It must have taken Royce’s much head-scratching to locate the issue, and many aircraft around that time were lost as a result.

Pete

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By: Trolly Aux - 1st March 2014 at 14:02

What was the skew gear problem i remember on Merlins ?

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By: PeterVerney - 28th February 2014 at 19:38

Because they are rotating the gear teeth only bear on a small area and wear can be a real factor. Note this stripped gear (not aeronautical). These wheels are about 15ins dia with a thickness of about about 3 ins. The teeth get worn down and can eventually strip because of excessive loading/ lack of lubrication.

A good dentist is essential.

http://i345.photobucket.com/albums/p398/navrad/P10508741280x864.jpg

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By: MerlinPete - 28th February 2014 at 07:10

You are right CD, it is because all the teeth of the spline transmit the torque simultaneously, whereas the gear tooth has to absorb it all on its own.
The cross sectional area of the splined shaft (quill shaft) is about half that of the prop shaft, because it transmits half the torque.
Pete

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By: powerandpassion - 28th February 2014 at 06:28

Prop

But the reduction-ratio is only a factor of the ratio of the teeth on the two gears; I am sure I could get exactly the same reduction-ratio with much smaller gears. The torque multiplication also is only a factor of the ratio of the teeth on the two gears.

Splines and gears are different but in transmitting the power, in different ways, they do exactly the same job. I suppose the main difference between them is the area of contact; in a spline (theoretically) the whole contact surface acts at the same time, in a gear only a tiny area of one tooth has to transmit the entire power of the engine.

There is a big prop cantilevered off the reduction gear shaft, so it is more than just transmitting torque force, deeper in the guts of the engine the splines off the crankshaft are more supported. The reduction gear case, bearings & gear not only support the prop but drag the rest of the engine and aeroplane after the prop.

The centrifugal reaction forces of the prop are enough to spin the aeroplane around its axis, so this force must be spread around the shafts and transmission bearings of the reduction case, the whole design must be sturdy.

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By: Creaking Door - 28th February 2014 at 00:34

But the reduction-ratio is only a factor of the ratio of the teeth on the two gears; I am sure I could get exactly the same reduction-ratio with much smaller gears. The torque multiplication also is only a factor of the ratio of the teeth on the two gears.

Splines and gears are different but in transmitting the power, in different ways, they do exactly the same job. I suppose the main difference between them is the area of contact; in a spline (theoretically) the whole contact surface acts at the same time, in a gear only a tiny area of one tooth has to transmit the entire power of the engine.

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By: smirky - 28th February 2014 at 00:24

Hmm…
I can see where you are coming from but the 400mm is required to get the required reduction ratio.

Also, splines are one thing and gears are another.

Most significant though is that the reduction gear is a torque multiplier (power= rpm x torque in appropriate units).

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