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Robbiesmurf

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Viewing 15 posts - 166 through 180 (of 473 total)
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  • in reply to: test pilot: "F-35 can't dogfight" #2168446
    Robbiesmurf
    Participant

    Are you saying that form drag does not affect the design? Because if it does, form drag is directly related to cross sectional area.

    Oh dear. Andraxxus will have to get back to Wiki again…..

    in reply to: test pilot: "F-35 can't dogfight" #2168597
    Robbiesmurf
    Participant

    Oh no, it is YOU who was/is showing lack of knowlegde.

    Other than wavedrag, which is highly irrelevant to BFM maneuverability as it is likely to happen below M0,9, cross-section has NOTHING to do with airframe drag, period. I suggest reading the pdf you posted. Specifically, focus on the formulae in section 2.2.

    Perhaps you could explain the difference between the F4J and F4K/M, why the K/M series are slower for instance?

    in reply to: test pilot: "F-35 can't dogfight" #2169169
    Robbiesmurf
    Participant

    I would also imagine that the first operational squadron will have only very experienced pilots (1,000+ hours). That is common.

    Robbiesmurf
    Participant

    MH17 report is to be published today, btw.

    13:15 local time the report will be read..

    Robbiesmurf
    Participant

    We cut off supplies of HP sauce to the States and embargo Top Gear!

    You DO know HP sauce is made in the Netherlands now?…

    in reply to: test pilot: "F-35 can't dogfight" #2169355
    Robbiesmurf
    Participant

    All the while, on F-22 vs F-15 comparisons, fact that F-15 has variable inlets featuring both internal and external compression mechanisms, is ignored.

    What are the internal and external compression mechanisms?

    in reply to: test pilot: "F-35 can't dogfight" #2169545
    Robbiesmurf
    Participant

    @Msphere,
    Further to your post about the manifolds. I have just studied some details of a modern engine and I understand what you mean now. Originally a ring-manifold (gutter) was fitted to engines which produces a vortex and a stable flame front. Now they use a straight manifold fitted perpendicular but angled to the airflow. That should give less cold loss and less problems with air mixing in fan engines. They are also used as ‘straighteners’ by the looks which would make the reheat more buzz resistant. The heat shield was quite large so I assume the temperature is very high.
    So you are right, they use more manifolds.

    in reply to: Contra props and single props #855018
    Robbiesmurf
    Participant

    A big problem with a propellor is tip-speed. If that approaches the speed of sound then the efficiency drops dramatically.
    One solution was to use wider chord (paddle) blades with a smaller diameter.

    in reply to: test pilot: "F-35 can't dogfight" #2169941
    Robbiesmurf
    Participant

    True, the number of manifolds can used at various stages of reheat. The amount of fuel flowing is metered using a VMO built into the reheat fuel control unit.
    It is used in a form of modulation to ensure smooth transition and is pressure ratio sensitive. This can be done purely by trimming the fuel to suit the selected power or fuel and nozzle opening.
    A typical example of pure fuel trimming was the RB145 which used a fixed nozzle opening. Others use a combination of fuel flow and nozzle opening, dependent on many factors.
    Part Throttle Reheat (PTR) has also been used to reduce the jump in power from max dry and min reheat. It is exactly what it says, engaging reheat at a lower than maximum rpm (typical, about 80%). This was done on one a/c type I worked on that was fitted with small fan (bypass engines). It also metered fuel over a number of manifolds dependent on power selected, but from min to max it was fully variable.
    Effectively what you are telling me is that the British have been able to produce fully modulated reheat since the ’60’s and P&W still cannot. That I doubt..
    One other point though, 7 augmentor spray manifolds would say there is a lot of metal in the pipe that could cause more blockage known as cold loss. RR seems to get away with 3 generally, even on fan engines.

    in reply to: test pilot: "F-35 can't dogfight" #2169966
    Robbiesmurf
    Participant

    Sinse People here seems to know so much about F135. Then how many different AB settings does it have?

    I assume variable from min to max. Fixed settings is ’50’s technology.

    in reply to: test pilot: "F-35 can't dogfight" #2170077
    Robbiesmurf
    Participant

    Just another question Andraxxus.
    Do they have reaction turbines in the F-135 engine for a faster throttle response?

    in reply to: F-16V #2170474
    Robbiesmurf
    Participant

    The bending moment you’re talking (downwards?) about I think would be in a static state (parked). When flying though, the lift on the wings causes a bending moment upwards. If you have more mass on the tips that could reduce the bending moment, so…
    Up-rigging ailerons has been used in the past on large a/c to reduce fatigue, it was effectively pushing the wing (tips) down. I don’t know if they still use it though.
    Apart from that, why would they put AMRAAM on the tips with promotional material? Poetic license I suppose, the sales department like to give things a spin..

    in reply to: test pilot: "F-35 can't dogfight" #2171276
    Robbiesmurf
    Participant

    A good answer, also the diesel engine.

    in reply to: test pilot: "F-35 can't dogfight" #2171309
    Robbiesmurf
    Participant

    Thats not it; A test flight’s purpose is designated by engineers, to test the aircraft who designed by engineers.

    Man in the cockpit of tested aircraft is only tasked with flying the plane, and doing things as instructed by engineers. Flight data is recorded by instruments, and relayed to engineers. This is even worse for the man in the cockpit of the other aircraft, as he is probably not even instructed to the details of his role in the test flight.

    In analogy, we have two cars, car#1 is making a turn, and following car#2 is purposely drifting while following. Then driver of car#1 comments “he oversteered all the way the turn, that means car#2 can’t turn as car#1”. And we would be laughing at it, as you can follow a vw beetle with a corvette, while drifting.

    The very fact, pilot claiming test flight is about F-35 testing its kinematics vs F-16 is the proof of his lack of knowledge.

    If such comparison was really wanted, F-16 flight test data is already available. F-35 would take-off, conduct maneuvers at incrementally changing various flight conditions and land. Comparison would be made *numerically* on the ground. “Hey F-16 can turn 19,65 deg/s, with 123 fps excess power. F-35 can turn 19,3 deg/s with 123 fps” It would not be in the lines of “hey go turn and burn with F-16.” and “how did it go, it was good yes?” Only a caveman would think test flight are made in such manners.

    But thats ok. Its completely excusable for a pilot think such things, just as a engine technician is not expected to know how to design a jet engine.

    @Robbiesmurf Since your very post obviously implied ME not answering to your “how afterburners work” question…

    I was delibaretely not answering your question because you were polluting the several different threads by constantly asking highly irrelevant to the topic question “how afterburners work” and you were not asking it to learn from the answers, but to prove yourself (by asking a question that no one can answer, then answer it yourself); make us acknowledge your “extensive knowledege” about jet engines. You know, last “The truth about the F-22” thread ended just because of your futile attempt to prove your greatness; for that alone, I think you should have been banned.

    And your answer to the question you asked was “Its a Temperature ratio, its a percentage blah blah” garbage.

    Question was “how afterburner/engine generates thrust.” Me, and a dozen answered correctly in the lines of “it happens at nozzle with “pressure and velocity” change” etc. FalconDude even suspected and said “I believe your question is not complete“, but no, you were both too arrogant and too ignorant to notice your own mistake OR accept the answers of others.

    Your answer was the answer to the question of thermodynamic equibilirium, not the dynamics on how *THRUST* is generated.

    Even then, temperature does not matter inside engine beyond material properties. The correct value you are looking for is not T, but H, the enthalpy. What you are doing, (in actual engineering POV) is this:

    You are assuming air is ideal gas in an isentropic process and use this form:

    entaphy change dH = Cp*dT + V*dP*(1-(1/V(dV/dT))*T)

    Then you are assuming coefficient of cubic thermal expansion=0, or pressure change is 0, Cp is constant, So your enthalphy change is proportional to T change. Then, if you assume 100% efficiency on an isentropic nozzle in all working conditions, and airspeed = 0, you can say T is proportional to thrust in terms of thermodynamics.

    Since no one asked about thermodynamics, you are answering to a question that no one’s asked. That is by ignoring 7 of 9 terms of enthalphy equation and taking 8th as constant, making a dozen assumptions, all the while you are dismissing everyone’s comment as “wikipedia quotes” or simply “wrong”.

    There is a difference between simplifying, and OVER-simplfying. Actual understanding of the subject tells you what you are doing is “simplifying” or going towards “way too inaccurate”. While you were trying to accuse me of “not understanding”, I didn’t answer at first, because I was exitedly waiting how you will humiliate yourself while you are trying to answer your own question, and your answer was “Temperature change, its a ratio, a percentage”. Well, thats what happens you try to be a smartass by reading a “how engines work” book directed at elementary school children. Since then, I am ignoring you on this subject; in case you haven’t noticed.

    Oh, you have also dismissed because I’ve said pressure change inside engine due to isentropy, you said “NOO pressure is the same.” Why? because your book says so? No, pressure is the same at *steady state*, that is you are picking one condition that thermodynamic equibilirium is valid. when you change RPM, fuel ratio, afterburner, pressure inside the engine DO change. Pressure even changes when aircraft is climbing or cruising at exact same RPM. I ignored your post because I was not in the mood of explaining compressor map to you starting from “systems theory” to explain what “constant pressure process” is and going through entire turbomachinary course. Its simply not worth it.

    Don’t mistake “ignoring someone” with inability to answer his comments.

    At the risk of humiliating myself, I was under the impression that a gas turbine engine runs on a constant pressure combustion cycle. Is that correct?

    in reply to: test pilot: "F-35 can't dogfight" #2171588
    Robbiesmurf
    Participant

    Interesting, you didn’t mention adiabatics….
    Fuel ratio, again interesting, the amplification ratio was a term used when fuel metering was purely hydrodynamic. For the Avon it was 60:1, an indication of it’s total FAR.

Viewing 15 posts - 166 through 180 (of 473 total)