No, of course not, if the aircraft remained stationary…

…but it can’t remain stationary if the propeller is generating take-off thrust. 🙂

How long is the conveyor?

Well, it will need to be as long as the normal take-off run for the aircraft plus a factor-of-safety so assuming aircraft starts at the right-hand end…it would need to be, well…runway length. 😀

Brakes on or off?

Take-off…so probably best with brakes off. 😉

Inertia?

Aircraft must overcome some extra inertia since aircraft wheels will be spinning twice as fast but not really a problem…

…the belt on the other hand will have loads of inertia to overcome because of its size (see point one) but then that’s not my problem! 🙂

Remember velocity is a vector not a scalar variable.

Hadn’t forgotten! 😀

He was asked by Michael Parkinson: “I imagine you have been advised because of tax also?”

Hamilton replied: “Also, that definitely adds to it.”

Good old Parkinson! 😀

http://news.bbc.co.uk/1/hi/england/beds/bucks/herts/7088652.stm

If you take it be direction as in direction of rotation…

Yes, so that question should read:

“If an aircraft is sitting on a conveyor belt…that rotates in the opposite direction to the direction that the aircraft wheels rotate, at the exact same speed as the aircraft wheels, will the plane take off?”

If the wheels of the plane move anti-clockwise…

Yes, so aircraft taking-off right-to-left.

…and the conveyer moves clockwise (dragging the plane to the right at same speed) then agreed the wheels will be doing twice the speed as they are covering twice the distance.

The conveyor rollers move clockwise dragging the belt to right (in an attempt to keep the aircraft stationary) but the aircraft will not be dragged with the belt because it is being pulled to the left by its propeller and its wheels are free-wheeling.

So the aircraft takes off as normal. 🙂

However relatively, its moving forward as fast as its moving back and therefore it goes nowhere (like a rolling road).

No, a rolling road is different because a car on a rolling road can only push against the surface of the rollers (which offer almost no resistance as they roll at the same speed as the car wheels but in the opposite direction).

The only way to keep the aircraft stationary would be to put it in a wind-tunnel that blew wind at the same speed as the aircraft was moving (or trying to as it would never actually move). In this case the wheels wouldn’t turn at all but the aircraft would happily take-off as soon as the wind tunnel reached take-off speed! 😀

There was an incident aboard the first escort carrier HMS Audacity (if memory serves) where a Martlet fighter damaged its propeller on landing.

Due to a shortage of aircraft and a lack of spares the bent propeller was cropped and the Martlet was put back into service.

The only noticeable difference being an increase in vibration. 😀

Assuming that this is a conventional propeller driven aircraft.

What makes the aircraft move forward is the thrust from the propeller so irrespective of what is happening to the wheels (which are free-wheeling) the aircraft will move forward and take-off normally with (almost) the same take-off run as it would from a stationary runway. 🙂

The only additional problem would be to overcome the momentum of the wheels (that would be spinning at twice the speed they would normally).

If an aircraft is sitting on a conveyor belt.. that rotates in the opposite direction to the wheels, at the exact same speed as the wheels, will the plane take off?

Yes, of course it will. 🙂

Why did nobody preserve a ………… before they were all gone? :confused:

(please fill in aircraft name as applicable.)