Well the IFF array doesn’t have to be that big for the starters. Thus i think there won’t be any problem embedding them into the main array as the earlier Russian ESA’s.
So i think the L-band array is able to do something more.
the L band array could be used to disrupt link-16 datalinks since both of them work in L band
That graph has 2 data points for F-22 at 8 and 10 GHz at exactly the same dB.
What the the person that made it has, is probably a single RCS number for I-band.
I-band being from 8-10 GHz.They then conclude that having equal RCS points at both 8 and 10 GHz is an accurate way to represent this [its not].
Which leads to people drawing the wrong conclusions [which is frustrating to try and explain*].
*Not blaming you, the reader cannot always be expected to have the knowledge and experience to interpret what has been done if its a haphazard representation of fact, its the Author’s fault.
iam not talking about the red point-line Armiga, iam talking about their computed blue line
they said they didn’t analysed how frequency from 1 Ghz – 2 Ghz interact with F-22 airframe but still draw that on their graph, which is not the right ways of doing things, it could lead to the conclusion that F-22 RCS suddenly increased significantly when frequency get below 2 Ghz while in reality that point could be 1.5 Ghz, 1.1 Ghz.. etc
also according to the blue graph F-22 will have higher RCS at 10 Ghz than 8 Ghz ( 1 dbsm vs – 20 dBsm) , after you factor in RAM, RCS at 10 Ghz can be reduced by another 29 dBsm, and RCS at 8 Ghz can be reduced by another 10-15 dBsm, thus overall F-22 still have lower RCS at 8 Ghz than 10 Ghz, hence i said the conclusion that target RCS will always proportional to wavelength is wrong
So after looking for a while, it turn out E-2C uses APS-145 radar, working in UHF frequency
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Are you sure it was it an E-2D ‘Advanced Hawkeye’ with AN/APY-9 & ADS-18*?
Can you produce hard evidence of both the aforementoed type and exercise debrief?
well to be fair it was the E-2C and E-3, what the frequency of E-2C radar?
in the June 2006 Northern Edge exercise, when even E-2C and E-3 AWACS aircraft reportedly weren’t much help against the F-22.
http://www.defenseindustrydaily.com/f-22-raptor-capabilities-and-controversies-019069/
Do you realise you’re trying to disprove long established (and tested) theories of electromagnetics?
*http://news.usni.org/2014/06/09/u-s-navys-secret-counter-stealth-weapon-hiding-plain-sight
iam not saying stealth aircraft doesn’t have higher RCS at very low frequency, what we are discussing is how much higher they would be
Also when people say the N036L-1-01 ( L band slat array on Su-35 PAK-FA ) can be used to counter stealth aircraft , they completely over look the fact that L band and VHF band radar need much bigger antenna to achieving the same gain with X band, so while in L band the RCS of stealth fighter is higher, the range of the L band cheek array itself is really short due to low gain
For example :
APG-81 have diameter of 80 cm, so it’s area is around 0.5 square meters
we dont know the exact size of N036L-1-01 ( L band thingy on T-50, Su-35)
but we can estimated it is around 2 meters long, the wing is about 6 cm thick
so it’s frontal area about 0.12 square meters, as a result APG-81 has about 4.16 times bigger aperture.
APG-81 work in X band so the wavelength is about 3 cm, N036L-1-01 work in L band so the wavelength is about 30 cm.
3*3 = 9 ( X band)
30*30 = 900 ( L-band)
If you put these 2 value on the equation
Gain = 4π ((AntennaArea * AntennaEfficiency) / Wavelength^2)
you will see that even if APG-81 and N036L-1-01 have equal out put and antenna efficiency, if both were to track the same target, APG-81’s energy will be 416 times more focused
No, because Jo’s graph is doesn’t include RAM.
Most RAM absorbing less than 28 dBsm at 10 Ghz while still absorbing around 10-15 dBsm at 8 Ghz, so overall F-22 still have lower RCS at 8 Ghz than 10 Ghz
another part that quite confusing about the simulation Sakura posted is that they said they didn’t analyse the frequency gap between 1 Ghz to 2 Ghz but then still have that on their graph ???
RAM is extremely effective in X-band, thus being a very good reason for the differential in X-band numbers.
Move away from X-band, and not only does shaping become less effective, but so does RAM. [There are materials which can act over a decent range of wavelengths, but effectivity is reduced.]
that depending mostly on the kind of RAM, some good at X band, some good at lower frequencies
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THAT’S BECAUSE E-3 SURVEILLANCE RADAR OPERATES IN S-BAND (E-F BAND), SHEEEESH!!!:
How about the E-2 in same exercise that wasn’t able to detect F-22 either ?
Look – an aircraft cannot always fly straight and level toward a radar. When it starts to present any kind of side aspect, RCS due to angle shoots up and couple that to RCS due to wavelength and low freq. detection range is hundreds of km for a useful search radar.
Singulars are not IADS. Again, you cannot fly straight and level all the time toward a radar – and you definitely cannot fly straight and level toward a series of interlocking radar.
i do understand that multiple radar stay far from others and being linked together can greatly reduce stealth aircraft effectiveness, because they can look at tge stealth fighter from their high RCS spike
my question however is : if F-22 ( and others stealth fighter ) have average frontal RCS of 20 dBsm at frequency from 0.2-0.8 Ghz, then why in real exercise AWACS cant detect them?, why BAE have to mentioned about the position of AWACS in their simulation ?
“Vehicles with low RCS values will generally show an RCS response proportional to the radar wavelength squared.”
Sentence starts 3 lines from top of page 19A-5.
oh, i see it now, it a bit confusing since they also marked their point on different page with the same number and letters.
Anyway, wouldn’t that conclusion strongly contradicting with the graphics simulation that Jo Sakura posted ?
in that simulation the F-22 model without RAM will have RCS of – 20 dBsm at around 8 Ghz, – 10 dBsm at 2 Ghz, but then at 10 Ghz it will have RCS of 1 dBsm
It can also be caused by direct illumination of the tips/edges by EM wave.
edge diffraction is used to talk about reflection due to surface wave, when you you illuminating something directly and get reflection, then they would simply call it spectacular return
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So, NOT nominated for the 2016 Nobel Prize in Physics iiizz…….SpudManWP!!! YAAAAAYY!!
did they actually analysed frequency range from 1 Ghz to 2 Ghz?
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and if F-22, F-35 have RCS of about 20 dBsm in L band, how do you explained what happened in exercise between E-2/3 and F-22? or BAE simulation? ( they obviously have more resources and experience in the matter, why do they think AWACS needed to be station at certain direction to detect stealth aircraft even though all AWACS use low frequency ? )
Or it’s not considered. Found the rad base brochure here :
It’s simulation includes
· Blocking
· Multiple Bounce Interaction
· Edge Diffraction
· Polarization
· Dielectric Materials
· Bistatic Computations
edge diffraction is the result from surface wave
Then i wonder why their polar plot somewhat only depicts Specular RCS result.
that probably due to the fact that reflection from surface wave is much lower than from spectacular return, thus they beng overlapped in the graph
It basically state that VHF Band radar will have 7-8 times detection range of X-band (assuming same gain etc..Only frequency change) L-band will have 2 times detection range compared to X-band.
to achieving same gain, you need much much bigger antenna at L band and VHF band compared to X band though
I don’t understand how they can jump from that assessment
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to that:
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Are they gonna run with their bulky radar on hands to keep tracking (or survive) the bad guy in stealthy mode*?
Also, I never realized that even at gun range, a radar will face difficulties in tracking an F22**
*22 km at 1200km/h is 1 min of detection and tracking time
** think at the much vaunted “radar lock” in the video b/w Rafale and F22!
they used radar with peak power of only 500 W in their example, with more powerful radar, the range will get longer, other factors stay the same, to double the range, transmitting power need to be increased by 16 times
Anyway, they also talk about very important factor, which is radar gain, radar gain basically mean how narrow the radar beam can be, the more focused the beam, the more power will be concentrated at the target, leading to longer range
Antenna Gain is computed through the following formula:
Gain = 4π ((AntennaArea * AntennaEfficiency) / Wavelength2)
Where:
Gain: Antenna gain at the center of the mainlobe.
Wavelength: The length of the radar’s wavelength.
AntennaArea= The area of the antenna’s aperture.
AntennaEfficiency = The efficiency factor of the antenna.
NOTE: Both AntennaArea and Wavelength must be in the same measurement units; e.g. if the antenna area is in square meters, the wavelength must be in meters as well.
X band wavelength is around 3.75 cm
L band wavelength is around 30 cm
VHF wavelength is around 1000 cm
so assuming same antenna efficiency ( around 0.6-0.8 for planar array and around 0.45 for Parabolic antenna ). To achieve the same gain value, L band radar will need 64 times bigger transmitting antenna compared to X band radar , VHF radar will need 71111 times bigger antenna compared to X band
Let’s try computational electromagnetic simulation of an F-22, shall we?……….’oh oh spaghettios’!!:
i dont know how accurate that simulation is, but there are 2 thing that need to take into consideration :.
1) VHF wavelength is around 10 meters long while L band wavelength is only around 0.15-0.3 meters long, thus it is a lot more likely that VHF wave can wrap around stealth fighter and create creeping Wave, resonant.. etc
2) that simulation still considered an F-22 without any RAM, i think we largely underestimate the importance of RAM.
in that simulation here is the average RCS of F-22 without any RAM
.i dont know how good are the fiber mat on F-35 is but there are many RAM with great absorbing characteristics
shows microwave absorption characteristics of rare earth doped MWCNT composites (a) 5wt% CNT and 1% CeO,and (b) 8wt% CNT and 1% CeO. The Fig.11 indicated the radar waves absorbing properties of carbon nanotubes were substantially improved after modification by rare earth oxides. The highest absorbing peak of the sample reachs –29.10 dB at 10.88 GHz and the bandwidth reaches 7.68 GHz(R<-10dB)loaded with 1wt% rare earth and 8% carbon nanotubes compared with undoped MWCNT with the absorbing peak value of 12.32dB and bandwidth of 2.80 GHz(R<-10 dB). The peak value increased by 16.87 dB and bandwidth increased by 4.88GHz.
http://www.intechopen.com/books/carbon-nanotubes-synthesis-characterization-applications/microwave-absorption-characteristics-of-carbon-nanotubes
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Yes, the detection range for a VLO will be reduced c.f. conventional airframe, but it won’t be to ranges that are significant. The horizon will be of more relevance.
While i agree that lower frequency reduce stealth aircraft effectiveness, i have to disagree with your assumption that at 1-2 Ghz, stealth aircraft won’t reduce enemy’s radar range significantly
From what we know F-22 was able to hide from E-2/E-3 radar in exercise, we also know that BAE promote a way to neutralise F-35’s stealth by positioning AWACS out side of it’s 50-60 degree frontal arcs. If stealth no longer work in low frequency how did f-22 hide from AWACS ?, why in their simulation BAE have to station their AWACS in some exact location to intercept f-35?
Sure, here’s a couple. First one is generalised comment, 3rd line in page 19A-5, the second link gives a table of geometric features and sensitivity to frequency/wavelength on page 133/134.
http://ftp.rta.nato.int/public//PubFullText/AGARD/AG/AGARD-AG-300-14///21cha19a.pdf
http://legacy.sname.org/sections/chesapeake/events/2005-05.pdf
i looked at the page you say but still cant find the part where they state ” target RCS is proportional to observe wavelength” can you screen shot that part and upload here?
Thanks.
and yes, it’s modeled using Physical Optics method. Thus it does not model RCS increase from Surface Travelling Wave and creeping wave.
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They also use Chu Stratton integral method which can be used to measure diffraction from surface wave