Do you have better access than me to the National Archives? I’m in North Yorkshire. There are some interesting documents in this list: http://www.enginehistory.org/References/UKNA/Prop-AVIA.shtml
Tom, I am not questioning the maths, it’s the geometry – the application of the maths – that’s off. You are drawing your triangles in the wrong places. Now whether you are being deliberately obtuse (I thank you) or not I don’t know, but please read what we have written and make the most of a fairly benign forum populated by people with esoteric but relevant experience, like Chris Cussen, as otherwise you will look a bit silly taking this further with other audiences,.
Oh, and there’s this – RM 2357
Spitfire I blade is t/c curve III, and there’s a later metal Rotol in there too – Curve IV
[ATTACH=CONFIG]256017[/ATTACH]
..but still no 1938-1940 metal Rotol. The field, as they say, is yours…
Ha – I didn’t mean to suggest that this was the font of all blade data. That came out wrong.
I have spent a several years now trying very many sources for UK blade data. There are copious US sources for the period that include blade design curves showing chord, t/c and twist, but when it comes to metal blades in the UK pre-1940 there’s an extraordinary ‘hole’ in the information.
The best route for me has been the measuring of relic blades – the guys at ARC dx were very helpful there – but only at certain points that enabled me to back up a couple of contentions, including de Havilland copying well documented US designs in some cases. I have nothing on metal Rotols pre 1940, but I am sure they are out there to measure, if only archaeological examples?
The US data, from NACA reports maiinly, does give a good general picture. It seems the Hamilton 6101 is as average a 1939-era blade as it gets.
If you do find anything I would be the keenest volunteer to receive any information – it has been a focus for a long time. I may not have pursued the Rotol avenues as much as DH, so I am sure it’s possible.
Here are some US values – check the h/b curves
[ATTACH=CONFIG]256016[/ATTACH]
Have you had a chance to read my TAH article? There’s a lot of t/c-related stuff in there from that period – also there’s some t/c and max speed data in M&S that looks very interesting plotted on a height graph. Are you working on these lines too?
Spitfire DH DP55409B blade, 1940, t/c 7.6% @ 0.7r
Apart from the 1.33 thing, Tom, you have it right there!
Now do the math (or just draw the diagram, much like the fish one) on the example of a body a few tens of feet under from the height of a satelite, using Snell’s law and applying the refractive index appropriately. As others have said it’s very close indeed to a 90 degree incidence, and therefore the deflection is tiny and the magnification on something the size of an Electra is a couple of centimetres at most.
Hi Ralph! I don’t really do Rotol. Anne might be better.. or Dairwin (spelling)? But if it’s a de Havilland spinny thing question, bring it on!
Ah yes: http://www.woodenpropeller.com/Britishprops.htm
It’s confused by the fact that the same prop assembly might be called Jablo, Rotol Jablo, Supermarine Jablo, or Vickers Jablo. Jablo made the blades, possibly to a Vickers drawing. Of course Rotol only really describes the hub in these cases.
Where it does say Rotol it’s fair to assume it’s not fixed pitch
9.1 is almost certainly a typo that has crept in somewhere. If you look at the figures in the table immediately underneath, it says 0.7 radius on the blade is at 45.22″. This equates to a full radius of 64.6″, and a full diameter of 129.2″ – more or less the standard DH Spitfire I 10′ 9″
Are you sure the 3001700 wasn’t the wooden fixed-pitch prop? M&S call it that, and there’s no indication it was Rotol manufacture – more weight behind the idea that this was just a Vickers designation and no indication of prop characteristics, or even manufacturer.
Cheers,
Matt
Meanwhile the Telegraph keep Teresa’s defence of Free Market capitalist dogma very low down in their news. http://www.telegraph.co.uk/ – see if you can find the story. They know how shrill it is starting to sound. It is a serious misjudgement on the part of May, very poor politics, she should have just acted like Corbyn hadn’t said anything.
“In words aimed at Mr Corbyn, she added: “We should never forget that raising the living standards, and protecting the jobs, of ordinary working people is the central aim of all economic policy.
“Helping each generation to live longer, fuller, more secure lives than the one which went before them. Not serving an abstract doctrine or an ideological concept, but serving the real interests of the British people.”
All this in support of the abstract doctrines of greed is good and trickledown. Funny old world.
I am not a fan if the on-line independent’s editorial style, but this is astute: http://www.independent.co.uk/voices/nationalisation-theresa-may-s-speech-in-defence-of-capitalism-proves-that-she-fears-jeremy-corbyn-s-a7971251.html. Not astute enough to see that this reported defense does more than pay Corbyn a compliment, it legitamises the opposition – precisely the opposite of the undermining tactic that Tory central office and its allied press have been employing since the re-emergence of a genuine opposition.
For the unconverted, Labour were not necessarily ‘setting the agenda’ until May’s speech. Now they are. Time to sack more advisers.
In the meantime – doesn’t the fact that the stated long-term goals of security and better lives have not been reached on behalf of the post-Thatcher generation suggest the neo-liberal free market experiment has in fact failed – and isn’t she rather stupidly highlighting that with this ill-advised knee-jerk?
That’s great – thanks Graham
I’d strongly recommend The Aviation Historian. The aim is to avoid the familiar stories / rich boys toys formula and let both real history and the real spirit of aviation come through in equal measure. It works.. those ‘in the know’ – and thank you to the forumite who tipped me off – swear by it as the best read out there. Sorry Key – I guess it’s different audiences, not suggesting your titles fail at all, just deliver different things.
TAH is not online, though, so this doesn’t answer the OP – sorry.
John, ‘our leftie justice system’? Once again you confuse leftie with liberal.
You really have a problem understanding that distinction, don’t you?
Once again. Please read carefully. Move your lips if it helps comprehension.
There is NOTHING in the theory or practice of socialism that would make any justice system more lenient.
Socialism.has nothing to say about law or the application of it. Just as it has nothing to say about teaching methods (cf..your ‘leftie educationalists’).
You are confused, and I expect.it comes from a deliberate conflation of two entirely different concepts by a particular strand of self-interested peddlers of lazy stereotypes.
Draw it on a piece of paper, no need for maths, not even one math. As your physic / physics department say, magnification does not change with height. Hence the dead rat example. Now, with that established..
The ratio of angles is a number related to the refractive index. If you change the angle of the light approaching the interface, in this case the water/air boundary, you change the angle at which it leaves. Dividing the sines of one into the other will always give the same result for the same media. That is how you draw the ‘bend’ of the rays traced from object to eye, and it is at the heart of how refraction works.
Yours is a very shallow angle of incidence indeed when looking vertically down from space – a triangle with a twenty foot base with an adjacent side the height of a satelite.
Apply Snell’s law to that.
You will see that to make the traced rays travel from object to eye while obeying the rules you will have to minutely adjust the ‘projected’ size on the surface. That is your magnification right there. It is TINY.
I am not going to contact a university (even my own university physics tutor) asking them to confirm a simple principle that is learned here pre-university to some bloke on a forum!
Ask the Physics/optics people to draw you a diagram. You will understand better when you see it. Currently I believe you are drawing a simple cone from eye to object, widening it using the refractive index of water. This will give you results that increase the apparent size of the object with height, and shows an incomplete understanding of refracrion.
Even better, simply ask your own academic contacts whether you have it right about the apparent size of the Electra. I am signing off here.
Ah, wait, I can see Taurus as well. Or is it just plain bull?
I shouldn’t rise to it, but here goes..
Tom, put down the scientific calculator and imagine if you will a dead rat at the bottom of a swimming pool. Standing on the edge of the pool it’s a dead rat that looks a bit closer to you than it really is, say a foot, because of refraction. Now, if you looked down on the pool from a tenth floor window, it wouldn’t suddenly look the size of a cow. It will still look like a dead rat. If viewing from the same angle it would still look a foot closer to you than it really is.
Think about where your triangles should be.
The refractive index refers to deflection within the medium – that’s where the angular difference is, and where any magnification occurs – not along the entire distance between object and eye. The deflection happens at the water surface, and all it does is alter the angle of a ray’s path by that factor. If the eye is looking vertically downwards from a great height, we are agreed that the angle from the surface of the water to the eye of any ray travelling from the edge of the object is tiny. Now apply the deflection to it – but only between the water surface and the object. Work in reverse so that the ray now touches the edge of the object, while keeping the ratio of angles constant. Now you will have drawn the actual path of photons (probably 😉 ) between the edge of the object and your eye.
As a final step continue the line drawn in the air on without deflection down through the water. Where that ray intersects the sea bed is where you’ll ‘see’ the edge of the object, and that will define the object’s apparent size.
It seems you are applying that angular deflection at the eye, not at the interface between media (sea surface) and your triangle base is therefore much larger than it should be?